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4142043314141 is a prime number
BaseRepresentation
bin111100010001100101000…
…001010011011111011101
3112122222100010020200201212
4330101211001103133131
51020330401042023031
612450454535114205
7605152460154365
oct74214501233735
915588303220655
104142043314141
1113576a3516987
1256a909b12965
13240792abbc45
1410469409d9a5
1572b2629812b
hex3c4650537dd

4142043314141 has 2 divisors, whose sum is σ = 4142043314142. Its totient is φ = 4142043314140.

The previous prime is 4142043314119. The next prime is 4142043314147. The reversal of 4142043314141 is 1414133402414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3710728005625 + 431315308516 = 1926325^2 + 656746^2 .

It is a cyclic number.

It is not a de Polignac number, because 4142043314141 - 226 = 4141976205277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4142043314098 and 4142043314107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4142043314147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071021657070 + 2071021657071.

It is an arithmetic number, because the mean of its divisors is an integer number (2071021657071).

Almost surely, 24142043314141 is an apocalyptic number.

It is an amenable number.

4142043314141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4142043314141 is an equidigital number, since it uses as much as digits as its factorization.

4142043314141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 4142043314141 its reverse (1414133402414), we get a palindrome (5556176716555).

The spelling of 4142043314141 in words is "four trillion, one hundred forty-two billion, forty-three million, three hundred fourteen thousand, one hundred forty-one".