Base | Representation |
---|---|
bin | 111100010010110101100… |
… | …111100010011100011111 |
3 | 112200002211100122120102102 |
4 | 330102311213202130133 |
5 | 1020341133222423033 |
6 | 12451241041315315 |
7 | 605231126524424 |
oct | 74226547423437 |
9 | 15602740576372 |
10 | 4143395514143 |
11 | 1358227827846 |
12 | 56b026935b3b |
13 | 240949ca27a2 |
14 | 1047818cbd4b |
15 | 72ba4d49de8 |
hex | 3c4b59e271f |
4143395514143 has 2 divisors, whose sum is σ = 4143395514144. Its totient is φ = 4143395514142.
The previous prime is 4143395514059. The next prime is 4143395514163. The reversal of 4143395514143 is 3414155933414.
4143395514143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4143395514143 - 210 = 4143395513119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4143395514163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071697757071 + 2071697757072.
It is an arithmetic number, because the mean of its divisors is an integer number (2071697757072).
Almost surely, 24143395514143 is an apocalyptic number.
4143395514143 is a deficient number, since it is larger than the sum of its proper divisors (1).
4143395514143 is an equidigital number, since it uses as much as digits as its factorization.
4143395514143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1555200, while the sum is 47.
The spelling of 4143395514143 in words is "four trillion, one hundred forty-three billion, three hundred ninety-five million, five hundred fourteen thousand, one hundred forty-three".
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