Base | Representation |
---|---|
bin | 101111000110110010110000… |
… | …1001110010111000000001001 |
3 | 2000100002110210200211021020121 |
4 | 1132031211201032113000021 |
5 | 413302202310320214233 |
6 | 4025125433422423241 |
7 | 153163541353505236 |
oct | 13615454116270011 |
9 | 2010073720737217 |
10 | 414350011101193 |
11 | 11002a942203072 |
12 | 3a57b984431b21 |
13 | 14a2806645916b |
14 | 744690cbd878d |
15 | 32d82dc02492d |
hex | 178d961397009 |
414350011101193 has 2 divisors, whose sum is σ = 414350011101194. Its totient is φ = 414350011101192.
The previous prime is 414350011101181. The next prime is 414350011101239. The reversal of 414350011101193 is 391101110053414.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 254221435928329 + 160128575172864 = 15944323^2 + 12654192^2 .
It is a cyclic number.
It is not a de Polignac number, because 414350011101193 - 213 = 414350011093001 is a prime.
It is not a weakly prime, because it can be changed into another prime (414350011101113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207175005550596 + 207175005550597.
It is an arithmetic number, because the mean of its divisors is an integer number (207175005550597).
Almost surely, 2414350011101193 is an apocalyptic number.
It is an amenable number.
414350011101193 is a deficient number, since it is larger than the sum of its proper divisors (1).
414350011101193 is an equidigital number, since it uses as much as digits as its factorization.
414350011101193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 34.
The spelling of 414350011101193 in words is "four hundred fourteen trillion, three hundred fifty billion, eleven million, one hundred one thousand, one hundred ninety-three".
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