Base | Representation |
---|---|
bin | 10010110110000110100000… |
… | …10110110110011101110111 |
3 | 12102201202100020122122102222 |
4 | 21123003100112312131313 |
5 | 20412433331032413444 |
6 | 224045515553152555 |
7 | 11505016016664515 |
oct | 1133032026663567 |
9 | 172652306578388 |
10 | 41441340122999 |
11 | 122281a0142673 |
12 | 4793738b5b75b |
13 | 1a17b94a9967b |
14 | a33ab32594b5 |
15 | 4bceb732beee |
hex | 25b0d05b6777 |
41441340122999 has 2 divisors, whose sum is σ = 41441340123000. Its totient is φ = 41441340122998.
The previous prime is 41441340122977. The next prime is 41441340123037. The reversal of 41441340122999 is 99922104314414.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41441340122999 - 212 = 41441340118903 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41441340122999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41441340122939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20720670061499 + 20720670061500.
It is an arithmetic number, because the mean of its divisors is an integer number (20720670061500).
Almost surely, 241441340122999 is an apocalyptic number.
41441340122999 is a deficient number, since it is larger than the sum of its proper divisors (1).
41441340122999 is an equidigital number, since it uses as much as digits as its factorization.
41441340122999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2239488, while the sum is 53.
The spelling of 41441340122999 in words is "forty-one trillion, four hundred forty-one billion, three hundred forty million, one hundred twenty-two thousand, nine hundred ninety-nine".
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