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4144244214251 is a prime number
BaseRepresentation
bin111100010011101000001…
…101000100100111101011
3112200012000111122000002202
4330103220031010213223
51020344403004324001
612451501200050415
7605261143412651
oct74235015044753
915605014560082
104144244214251
111358622900799
1256b223003a0b
13240a53a771bb
141048224d2dd1
1572c045e196b
hex3c4e83449eb

4144244214251 has 2 divisors, whose sum is σ = 4144244214252. Its totient is φ = 4144244214250.

The previous prime is 4144244214221. The next prime is 4144244214281. The reversal of 4144244214251 is 1524124424414.

4144244214251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (4144244214221) and next prime (4144244214281).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4144244214251 is a prime.

It is not a weakly prime, because it can be changed into another prime (4144244214221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072122107125 + 2072122107126.

It is an arithmetic number, because the mean of its divisors is an integer number (2072122107126).

Almost surely, 24144244214251 is an apocalyptic number.

4144244214251 is a deficient number, since it is larger than the sum of its proper divisors (1).

4144244214251 is an equidigital number, since it uses as much as digits as its factorization.

4144244214251 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 163840, while the sum is 38.

Adding to 4144244214251 its reverse (1524124424414), we get a palindrome (5668368638665).

The spelling of 4144244214251 in words is "four trillion, one hundred forty-four billion, two hundred forty-four million, two hundred fourteen thousand, two hundred fifty-one".