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4144430113303 is a prime number
BaseRepresentation
bin111100010011110011010…
…010001110001000010111
3112200012111110102122122211
4330103303102032020113
51020400243102111203
612451531440334251
7605265561500464
oct74236322161027
915605443378584
104144430113303
111358708832477
1256b275314387
13240a8343513c
1410483d08466b
1572c15ab2c6d
hex3c4f348e217

4144430113303 has 2 divisors, whose sum is σ = 4144430113304. Its totient is φ = 4144430113302.

The previous prime is 4144430113249. The next prime is 4144430113309. The reversal of 4144430113303 is 3033110344414.

It is a happy number.

4144430113303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4144430113303 - 233 = 4135840178711 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4144430113309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072215056651 + 2072215056652.

It is an arithmetic number, because the mean of its divisors is an integer number (2072215056652).

Almost surely, 24144430113303 is an apocalyptic number.

4144430113303 is a deficient number, since it is larger than the sum of its proper divisors (1).

4144430113303 is an equidigital number, since it uses as much as digits as its factorization.

4144430113303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4144430113303 its reverse (3033110344414), we get a palindrome (7177540457717).

The spelling of 4144430113303 in words is "four trillion, one hundred forty-four billion, four hundred thirty million, one hundred thirteen thousand, three hundred three".