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41473721320597 is a prime number
BaseRepresentation
bin10010110111000010110100…
…11011010100010010010101
312102211211220221120220211201
421123201122123110102111
520414001140124224342
6224112433050432501
711510243322426436
oct1133413233242225
9172754827526751
1041473721320597
111223a9a75166a5
124799a75432731
131a1ac55596117
14a354a5a2b48d
154bdc60015db7
hex25b85a6d4495

41473721320597 has 2 divisors, whose sum is σ = 41473721320598. Its totient is φ = 41473721320596.

The previous prime is 41473721320531. The next prime is 41473721320609. The reversal of 41473721320597 is 79502312737414.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41439938512996 + 33782807601 = 6437386^2 + 183801^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41473721320597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41473721320897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20736860660298 + 20736860660299.

It is an arithmetic number, because the mean of its divisors is an integer number (20736860660299).

Almost surely, 241473721320597 is an apocalyptic number.

It is an amenable number.

41473721320597 is a deficient number, since it is larger than the sum of its proper divisors (1).

41473721320597 is an equidigital number, since it uses as much as digits as its factorization.

41473721320597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8890560, while the sum is 55.

The spelling of 41473721320597 in words is "forty-one trillion, four hundred seventy-three billion, seven hundred twenty-one million, three hundred twenty thousand, five hundred ninety-seven".