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414906562453 is a prime number
BaseRepresentation
bin1100000100110100101…
…10111011011110010101
31110122221112220012110111
412002122112323132111
523244212034444303
6514334435323021
741655525406525
oct6023226733625
91418845805414
10414906562453
1114aa62a353a9
12684b3450471
1330182a008b6
141611dc23685
15abd5402b6d
hex609a5bb795

414906562453 has 2 divisors, whose sum is σ = 414906562454. Its totient is φ = 414906562452.

The previous prime is 414906562451. The next prime is 414906562529. The reversal of 414906562453 is 354265609414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 279970090884 + 134936471569 = 529122^2 + 367337^2 .

It is a cyclic number.

It is not a de Polignac number, because 414906562453 - 21 = 414906562451 is a prime.

Together with 414906562451, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 414906562397 and 414906562406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414906562451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207453281226 + 207453281227.

It is an arithmetic number, because the mean of its divisors is an integer number (207453281227).

Almost surely, 2414906562453 is an apocalyptic number.

It is an amenable number.

414906562453 is a deficient number, since it is larger than the sum of its proper divisors (1).

414906562453 is an equidigital number, since it uses as much as digits as its factorization.

414906562453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3110400, while the sum is 49.

The spelling of 414906562453 in words is "four hundred fourteen billion, nine hundred six million, five hundred sixty-two thousand, four hundred fifty-three".