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41497133 is a prime number
BaseRepresentation
bin1001111001001…
…1001000101101
32220002021100212
42132103020231
541110402013
64041232205
71012501616
oct236231055
986067325
1041497133
1121473457
1211a92665
13879c122
145722c0d
15399a6a8
hex279322d

41497133 has 2 divisors, whose sum is σ = 41497134. Its totient is φ = 41497132.

The previous prime is 41497087. The next prime is 41497151. The reversal of 41497133 is 33179414.

41497133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39904489 + 1592644 = 6317^2 + 1262^2 .

It is a cyclic number.

It is not a de Polignac number, because 41497133 - 212 = 41493037 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41497133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41497333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20748566 + 20748567.

It is an arithmetic number, because the mean of its divisors is an integer number (20748567).

Almost surely, 241497133 is an apocalyptic number.

It is an amenable number.

41497133 is a deficient number, since it is larger than the sum of its proper divisors (1).

41497133 is an equidigital number, since it uses as much as digits as its factorization.

41497133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9072, while the sum is 32.

The square root of 41497133 is about 6441.8268371635. The cubic root of 41497133 is about 346.2098057058.

The spelling of 41497133 in words is "forty-one million, four hundred ninety-seven thousand, one hundred thirty-three".