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415203011132 = 227131140667613
BaseRepresentation
bin1100000101011000000…
…01110010101000111100
31110200201012201100121012
412002230001302220330
523300313432324012
6514424105254352
741666055235430
oct6025401625074
91420635640535
10415203011132
111500a5303708
12685767943b8
13301cc257110
141614b3509c0
15ac0145e622
hex60ac072a3c

415203011132 has 24 divisors (see below), whose sum is σ = 894283409376. Its totient is φ = 164256136128.

The previous prime is 415203011107. The next prime is 415203011137. The reversal of 415203011132 is 231110302514.

It is a junction number, because it is equal to n+sod(n) for n = 415203011098 and 415203011107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (415203011137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570333443 + ... + 570334170.

It is an arithmetic number, because the mean of its divisors is an integer number (37261808724).

Almost surely, 2415203011132 is an apocalyptic number.

It is an amenable number.

415203011132 is an abundant number, since it is smaller than the sum of its proper divisors (479080398244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

415203011132 is a wasteful number, since it uses less digits than its factorization.

415203011132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1140667637 (or 1140667635 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 415203011132 its reverse (231110302514), we get a palindrome (646313313646).

The spelling of 415203011132 in words is "four hundred fifteen billion, two hundred three million, eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 7 13 14 26 28 52 91 182 364 1140667613 2281335226 4562670452 7984673291 14828678969 15969346582 29657357938 31938693164 59314715876 103800752783 207601505566 415203011132