Base | Representation |
---|---|
bin | 10010111100010111001110… |
… | …10111010100111010011111 |
3 | 12110111022122022220202102012 |
4 | 21132023213113110322133 |
5 | 20424444424432112404 |
6 | 224332415321221435 |
7 | 11526403161633164 |
oct | 1136134727247237 |
9 | 173438568822365 |
10 | 41656474488479 |
11 | 12300458959634 |
12 | 480937903187b |
13 | 1a3225b71b396 |
14 | a4028133a06b |
15 | 4c38a92a7a6e |
hex | 25e2e75d4e9f |
41656474488479 has 2 divisors, whose sum is σ = 41656474488480. Its totient is φ = 41656474488478.
The previous prime is 41656474488443. The next prime is 41656474488481. The reversal of 41656474488479 is 97488447465614.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41656474488479 is a prime.
Together with 41656474488481, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41656474088479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20828237244239 + 20828237244240.
It is an arithmetic number, because the mean of its divisors is an integer number (20828237244240).
Almost surely, 241656474488479 is an apocalyptic number.
41656474488479 is a deficient number, since it is larger than the sum of its proper divisors (1).
41656474488479 is an equidigital number, since it uses as much as digits as its factorization.
41656474488479 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5202247680, while the sum is 77.
The spelling of 41656474488479 in words is "forty-one trillion, six hundred fifty-six billion, four hundred seventy-four million, four hundred eighty-eight thousand, four hundred seventy-nine".
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