Base | Representation |
---|---|
bin | 100111000111100101… |
… | …001110111001011111 |
3 | 11000102021022012000112 |
4 | 213013211032321133 |
5 | 1142010300210444 |
6 | 31143532520235 |
7 | 3014606505533 |
oct | 470745167137 |
9 | 130367265015 |
10 | 42003131999 |
11 | 168a4744834 |
12 | 818292007b |
13 | 3c6508537a |
14 | 206663dbc3 |
15 | 115c7b769e |
hex | 9c794ee5f |
42003131999 has 2 divisors, whose sum is σ = 42003132000. Its totient is φ = 42003131998.
The previous prime is 42003131993. The next prime is 42003132001. The reversal of 42003131999 is 99913130024.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-42003131999 is a prime.
Together with 42003132001, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42003131993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21001565999 + 21001566000.
It is an arithmetic number, because the mean of its divisors is an integer number (21001566000).
Almost surely, 242003131999 is an apocalyptic number.
42003131999 is a deficient number, since it is larger than the sum of its proper divisors (1).
42003131999 is an equidigital number, since it uses as much as digits as its factorization.
42003131999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 42003131999 in words is "forty-two billion, three million, one hundred thirty-one thousand, nine hundred ninety-nine".
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