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4201311224167 is a prime number
BaseRepresentation
bin111101001000110001101…
…010011100000101100111
3112212122022121021110211121
4331020301222130011213
51022313241133133132
612534020012114411
7612351260116111
oct75106152340547
915778277243747
104201311224167
11137a847726a02
1257a2aa765a07
132462499826a5
141074b76243b1
15744445da497
hex3d231a9c167

4201311224167 has 2 divisors, whose sum is σ = 4201311224168. Its totient is φ = 4201311224166.

The previous prime is 4201311224119. The next prime is 4201311224249. The reversal of 4201311224167 is 7614221131024.

4201311224167 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4201311224167 is a prime.

It is a super-2 number, since 2×42013112241672 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4201311224567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2100655612083 + 2100655612084.

It is an arithmetic number, because the mean of its divisors is an integer number (2100655612084).

Almost surely, 24201311224167 is an apocalyptic number.

4201311224167 is a deficient number, since it is larger than the sum of its proper divisors (1).

4201311224167 is an equidigital number, since it uses as much as digits as its factorization.

4201311224167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

The spelling of 4201311224167 in words is "four trillion, two hundred one billion, three hundred eleven million, two hundred twenty-four thousand, one hundred sixty-seven".