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420132515223101 is a prime number
BaseRepresentation
bin101111110000110111011100…
…1010101000001011000111101
32001002120021110100111102212112
41133201232321111001120331
5420031422342344114401
64045314114002143405
7154331400245532452
oct13741567125013075
92032507410442775
10420132515223101
1111195a22101413a
123b1545b5351b65
13150574318357b5
1475a6745025829
153388926a5e3bb
hex17e1bb954163d

420132515223101 has 2 divisors, whose sum is σ = 420132515223102. Its totient is φ = 420132515223100.

The previous prime is 420132515223017. The next prime is 420132515223229. The reversal of 420132515223101 is 101322515231024.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 356374126759876 + 63758388463225 = 18877874^2 + 7984885^2 .

It is a cyclic number.

It is not a de Polignac number, because 420132515223101 - 226 = 420132448114237 is a prime.

It is a super-4 number, since 4×4201325152231014 (a number of 60 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (420132565223101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210066257611550 + 210066257611551.

It is an arithmetic number, because the mean of its divisors is an integer number (210066257611551).

Almost surely, 2420132515223101 is an apocalyptic number.

It is an amenable number.

420132515223101 is a deficient number, since it is larger than the sum of its proper divisors (1).

420132515223101 is an equidigital number, since it uses as much as digits as its factorization.

420132515223101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 420132515223101 in words is "four hundred twenty trillion, one hundred thirty-two billion, five hundred fifteen million, two hundred twenty-three thousand, one hundred one".