Base | Representation |
---|---|
bin | 111101001001100111011… |
… | …110011010001110110101 |
3 | 112212201122112002022000121 |
4 | 331021213132122032311 |
5 | 1022322113243244001 |
6 | 12534245342411541 |
7 | 612412531664521 |
oct | 75114736321665 |
9 | 15781575068017 |
10 | 4202214040501 |
11 | 1380170302204 |
12 | 57a500b90bb1 |
13 | 246361a23c39 |
14 | 1075614b4d81 |
15 | 744989c16a1 |
hex | 3d26779a3b5 |
4202214040501 has 2 divisors, whose sum is σ = 4202214040502. Its totient is φ = 4202214040500.
The previous prime is 4202214040487. The next prime is 4202214040529. The reversal of 4202214040501 is 1050404122024.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4032264802500 + 169949238001 = 2008050^2 + 412249^2 .
It is a cyclic number.
It is not a de Polignac number, because 4202214040501 - 237 = 4064775087029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4202214080501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2101107020250 + 2101107020251.
It is an arithmetic number, because the mean of its divisors is an integer number (2101107020251).
Almost surely, 24202214040501 is an apocalyptic number.
It is an amenable number.
4202214040501 is a deficient number, since it is larger than the sum of its proper divisors (1).
4202214040501 is an equidigital number, since it uses as much as digits as its factorization.
4202214040501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 4202214040501 its reverse (1050404122024), we get a palindrome (5252618162525).
The spelling of 4202214040501 in words is "four trillion, two hundred two billion, two hundred fourteen million, forty thousand, five hundred one".
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