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4204265471983 is a prime number
BaseRepresentation
bin111101001011100001101…
…111111111111111101111
3112212220221111012210222101
4331023201233333333233
51022340313430100413
612535225103555531
7612514421605363
oct75134157777757
915786844183871
104204265471983
111381023288025
1257a993bbbba7
132465caa38115
141076b7b1b2a3
1574568b42edd
hex3d2e1bfffef

4204265471983 has 2 divisors, whose sum is σ = 4204265471984. Its totient is φ = 4204265471982.

The previous prime is 4204265471981. The next prime is 4204265472023. The reversal of 4204265471983 is 3891745624024.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4204265471983 - 21 = 4204265471981 is a prime.

Together with 4204265471981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4204265471981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2102132735991 + 2102132735992.

It is an arithmetic number, because the mean of its divisors is an integer number (2102132735992).

It is a 1-persistent number, because it is pandigital, but 2⋅4204265471983 = 8408530943966 is not.

Almost surely, 24204265471983 is an apocalyptic number.

4204265471983 is a deficient number, since it is larger than the sum of its proper divisors (1).

4204265471983 is an equidigital number, since it uses as much as digits as its factorization.

4204265471983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11612160, while the sum is 55.

The spelling of 4204265471983 in words is "four trillion, two hundred four billion, two hundred sixty-five million, four hundred seventy-one thousand, nine hundred eighty-three".