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420714659832517 is a prime number
BaseRepresentation
bin101111110101000110100001…
…1110110011110001011000101
32001011121221002000021200011101
41133222031003312132023011
5420120442110404120032
64050441351353340101
7154421426320214251
oct13752150366361305
92034557060250141
10420714659832517
111120640a3515496
123b2293a0407631
131509a2b71c4b1b
1475c69abb63261
153398b4908ade7
hex17ea343d9e2c5

420714659832517 has 2 divisors, whose sum is σ = 420714659832518. Its totient is φ = 420714659832516.

The previous prime is 420714659832461. The next prime is 420714659832559. The reversal of 420714659832517 is 715238956417024.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 264583862089156 + 156130797743361 = 16266034^2 + 12495231^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-420714659832517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (420714659839517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210357329916258 + 210357329916259.

It is an arithmetic number, because the mean of its divisors is an integer number (210357329916259).

It is a 1-persistent number, because it is pandigital, but 2⋅420714659832517 = 841429319665034 is not.

Almost surely, 2420714659832517 is an apocalyptic number.

It is an amenable number.

420714659832517 is a deficient number, since it is larger than the sum of its proper divisors (1).

420714659832517 is an equidigital number, since it uses as much as digits as its factorization.

420714659832517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 101606400, while the sum is 64.

The spelling of 420714659832517 in words is "four hundred twenty trillion, seven hundred fourteen billion, six hundred fifty-nine million, eight hundred thirty-two thousand, five hundred seventeen".