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42132210431 is a prime number
BaseRepresentation
bin100111001111010001…
…101000001011111111
311000202021012001100012
4213033101220023333
51142241321213211
631204423253435
73021034610513
oct471721501377
9130667161305
1042132210431
1116960597323
1281b9baa27b
133c85a3a53c
142079840143
151168cb2d8b
hex9cf4682ff

42132210431 has 2 divisors, whose sum is σ = 42132210432. Its totient is φ = 42132210430.

The previous prime is 42132210403. The next prime is 42132210433. The reversal of 42132210431 is 13401223124.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42132210431 is a prime.

It is a super-2 number, since 2×421322104312 (a number of 22 digits) contains 22 as substring.

Together with 42132210433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 42132210397 and 42132210406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42132210433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21066105215 + 21066105216.

It is an arithmetic number, because the mean of its divisors is an integer number (21066105216).

Almost surely, 242132210431 is an apocalyptic number.

42132210431 is a deficient number, since it is larger than the sum of its proper divisors (1).

42132210431 is an equidigital number, since it uses as much as digits as its factorization.

42132210431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 42132210431 its reverse (13401223124), we get a palindrome (55533433555).

The spelling of 42132210431 in words is "forty-two billion, one hundred thirty-two million, two hundred ten thousand, four hundred thirty-one".