| Base | Representation |
|---|---|
| bin | 1111101100100010… |
| … | …0101110010000101 |
| 3 | 101212122010111111000 |
| 4 | 3323020211302011 |
| 5 | 32112103130000 |
| 6 | 1534030203513 |
| 7 | 206260512021 |
| oct | 37310456205 |
| 9 | 11778114430 |
| 10 | 4213333125 |
| 11 | 18723535a1 |
| 12 | 997053599 |
| 13 | 521b96731 |
| 14 | 2bd807381 |
| 15 | 199d65000 |
| hex | fb225c85 |
4213333125 has 160 divisors (see below), whose sum is σ = 8704713600. Its totient is φ = 2001024000.
The previous prime is 4213333073. The next prime is 4213333127. The reversal of 4213333125 is 5213333124.
4213333125 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4213333125 - 219 = 4212808837 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4213333127) by changing a digit.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 5450239 + ... + 5451011.
It is an arithmetic number, because the mean of its divisors is an integer number (54404460).
Almost surely, 24213333125 is an apocalyptic number.
4213333125 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
4213333125 is an abundant number, since it is smaller than the sum of its proper divisors (4491380475).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4213333125 is a wasteful number, since it uses less digits than its factorization.
4213333125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 838 (or 817 counting only the distinct ones).
The product of its digits is 6480, while the sum is 27.
The square root of 4213333125 is about 64910.1927666218. The cubic root of 4213333125 is about 1615.1341477836.
Adding to 4213333125 its reverse (5213333124), we get a palindrome (9426666249).
Subtracting 4213333125 from its reverse (5213333124), we obtain a palindrome (999999999).
It can be divided in two parts, 4213333 and 125, that multiplied together give a palindrome (526666625).
The spelling of 4213333125 in words is "four billion, two hundred thirteen million, three hundred thirty-three thousand, one hundred twenty-five".
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