Base | Representation |
---|---|
bin | 1100010000110011101… |
… | …01101101100000111111 |
3 | 1111021112221010012200221 |
4 | 12020121311231200333 |
5 | 23400401104233341 |
6 | 521321105002211 |
7 | 42304130335021 |
oct | 6103165554077 |
9 | 1437487105627 |
10 | 421340305471 |
11 | 152764688798 |
12 | 697aa023367 |
13 | 309698c3827 |
14 | 1657049c011 |
15 | ae60166ed1 |
hex | 6219d6d83f |
421340305471 has 2 divisors, whose sum is σ = 421340305472. Its totient is φ = 421340305470.
The previous prime is 421340305439. The next prime is 421340305483. The reversal of 421340305471 is 174503043124.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 421340305471 - 25 = 421340305439 is a prime.
It is a super-3 number, since 3×4213403054713 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (421340305411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210670152735 + 210670152736.
It is an arithmetic number, because the mean of its divisors is an integer number (210670152736).
Almost surely, 2421340305471 is an apocalyptic number.
421340305471 is a deficient number, since it is larger than the sum of its proper divisors (1).
421340305471 is an equidigital number, since it uses as much as digits as its factorization.
421340305471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 421340305471 its reverse (174503043124), we get a palindrome (595843348595).
The spelling of 421340305471 in words is "four hundred twenty-one billion, three hundred forty million, three hundred five thousand, four hundred seventy-one".
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