Base | Representation |
---|---|
bin | 111101011101010010101… |
… | …100010111001100110111 |
3 | 112221202011211201001120122 |
4 | 331131102230113030313 |
5 | 1023143400043304142 |
6 | 12552101541522155 |
7 | 614061210332354 |
oct | 75352254271467 |
9 | 15852154631518 |
10 | 4223340213047 |
11 | 13891214a233a |
12 | 58261811335b |
13 | 24834a814357 |
14 | 1085a718d62b |
15 | 74cd35431d2 |
hex | 3d752b17337 |
4223340213047 has 2 divisors, whose sum is σ = 4223340213048. Its totient is φ = 4223340213046.
The previous prime is 4223340213019. The next prime is 4223340213049. The reversal of 4223340213047 is 7403120433224.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4223340213047 - 222 = 4223336018743 is a prime.
Together with 4223340213049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 4223340212998 and 4223340213016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4223340213049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2111670106523 + 2111670106524.
It is an arithmetic number, because the mean of its divisors is an integer number (2111670106524).
Almost surely, 24223340213047 is an apocalyptic number.
4223340213047 is a deficient number, since it is larger than the sum of its proper divisors (1).
4223340213047 is an equidigital number, since it uses as much as digits as its factorization.
4223340213047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 4223340213047 in words is "four trillion, two hundred twenty-three billion, three hundred forty million, two hundred thirteen thousand, forty-seven".
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