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42251513114051 is a prime number
BaseRepresentation
bin10011001101101011100100…
…11011100010110111000011
312112121012112121001212122222
421212311302123202313003
521014222044324122201
6225510024400121255
711620366611535553
oct1146656233426703
9175535477055588
1042251513114051
111250a84772708a
1248a476230622b
131a763ba522077
14a60dac6d5163
154d40d379d91b
hex266d726e2dc3

42251513114051 has 2 divisors, whose sum is σ = 42251513114052. Its totient is φ = 42251513114050.

The previous prime is 42251513114029. The next prime is 42251513114053. The reversal of 42251513114051 is 15041131515224.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42251513114051 - 214 = 42251513097667 is a prime.

Together with 42251513114053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (42251513114053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21125756557025 + 21125756557026.

It is an arithmetic number, because the mean of its divisors is an integer number (21125756557026).

Almost surely, 242251513114051 is an apocalyptic number.

42251513114051 is a deficient number, since it is larger than the sum of its proper divisors (1).

42251513114051 is an equidigital number, since it uses as much as digits as its factorization.

42251513114051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 35.

Adding to 42251513114051 its reverse (15041131515224), we get a palindrome (57292644629275).

The spelling of 42251513114051 in words is "forty-two trillion, two hundred fifty-one billion, five hundred thirteen million, one hundred fourteen thousand, fifty-one".