Base | Representation |
---|---|
bin | 10011001101101011100100… |
… | …11011100010110111000011 |
3 | 12112121012112121001212122222 |
4 | 21212311302123202313003 |
5 | 21014222044324122201 |
6 | 225510024400121255 |
7 | 11620366611535553 |
oct | 1146656233426703 |
9 | 175535477055588 |
10 | 42251513114051 |
11 | 1250a84772708a |
12 | 48a476230622b |
13 | 1a763ba522077 |
14 | a60dac6d5163 |
15 | 4d40d379d91b |
hex | 266d726e2dc3 |
42251513114051 has 2 divisors, whose sum is σ = 42251513114052. Its totient is φ = 42251513114050.
The previous prime is 42251513114029. The next prime is 42251513114053. The reversal of 42251513114051 is 15041131515224.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42251513114051 - 214 = 42251513097667 is a prime.
Together with 42251513114053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (42251513114053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21125756557025 + 21125756557026.
It is an arithmetic number, because the mean of its divisors is an integer number (21125756557026).
Almost surely, 242251513114051 is an apocalyptic number.
42251513114051 is a deficient number, since it is larger than the sum of its proper divisors (1).
42251513114051 is an equidigital number, since it uses as much as digits as its factorization.
42251513114051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 42251513114051 its reverse (15041131515224), we get a palindrome (57292644629275).
The spelling of 42251513114051 in words is "forty-two trillion, two hundred fifty-one billion, five hundred thirteen million, one hundred fourteen thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •