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4233101113231 is a prime number
BaseRepresentation
bin111101100110011000011…
…111001111011110001111
3112222200101002120011102021
4331212120133033132033
51023323342341110411
613000354303511011
7614555122531324
oct75463037173617
915880332504367
104233101113231
1113922802490a1
125844a0bb8467
13249244b07633
14108c51672b4b
15751a5421a71
hex3d9987cf78f

4233101113231 has 2 divisors, whose sum is σ = 4233101113232. Its totient is φ = 4233101113230.

The previous prime is 4233101113223. The next prime is 4233101113243. The reversal of 4233101113231 is 1323111013324.

4233101113231 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4233101113231 - 23 = 4233101113223 is a prime.

It is a super-2 number, since 2×42331011132312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4233101113196 and 4233101113205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4233101513231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116550556615 + 2116550556616.

It is an arithmetic number, because the mean of its divisors is an integer number (2116550556616).

Almost surely, 24233101113231 is an apocalyptic number.

4233101113231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233101113231 is an equidigital number, since it uses as much as digits as its factorization.

4233101113231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 4233101113231 its reverse (1323111013324), we get a palindrome (5556212126555).

The spelling of 4233101113231 in words is "four trillion, two hundred thirty-three billion, one hundred one million, one hundred thirteen thousand, two hundred thirty-one".