Base | Representation |
---|---|
bin | 100111011011110110… |
… | …001001101101001101 |
3 | 11001021222000221012221 |
4 | 213123312021231031 |
5 | 1143204314032001 |
6 | 31241355455341 |
7 | 3026205336445 |
oct | 473366115515 |
9 | 131258027187 |
10 | 42343111501 |
11 | 16a59645429 |
12 | 8258757551 |
13 | 3cba640582 |
14 | 209985d125 |
15 | 117c5721a1 |
hex | 9dbd89b4d |
42343111501 has 2 divisors, whose sum is σ = 42343111502. Its totient is φ = 42343111500.
The previous prime is 42343111469. The next prime is 42343111511. The reversal of 42343111501 is 10511134324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23860980900 + 18482130601 = 154470^2 + 135949^2 .
It is a cyclic number.
It is not a de Polignac number, because 42343111501 - 25 = 42343111469 is a prime.
It is a super-2 number, since 2×423431115012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42343111511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21171555750 + 21171555751.
It is an arithmetic number, because the mean of its divisors is an integer number (21171555751).
Almost surely, 242343111501 is an apocalyptic number.
It is an amenable number.
42343111501 is a deficient number, since it is larger than the sum of its proper divisors (1).
42343111501 is an equidigital number, since it uses as much as digits as its factorization.
42343111501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 42343111501 its reverse (10511134324), we get a palindrome (52854245825).
The spelling of 42343111501 in words is "forty-two billion, three hundred forty-three million, one hundred eleven thousand, five hundred one".
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