Base | Representation |
---|---|
bin | 111101110110100001011… |
… | …101010111100000001111 |
3 | 120001100002212201022112011 |
4 | 331312201131113200033 |
5 | 1024114340430022332 |
6 | 13012342105522051 |
7 | 616040440342342 |
oct | 75664135274017 |
9 | 16040085638464 |
10 | 4250431485967 |
11 | 1399663846697 |
12 | 587918aa3327 |
13 | 24aa773a1364 |
14 | 109a17190459 |
15 | 7586bb06e47 |
hex | 3dda175780f |
4250431485967 has 2 divisors, whose sum is σ = 4250431485968. Its totient is φ = 4250431485966.
The previous prime is 4250431485961. The next prime is 4250431485973. The reversal of 4250431485967 is 7695841340524.
It is a balanced prime because it is at equal distance from previous prime (4250431485961) and next prime (4250431485973).
It is a cyclic number.
It is not a de Polignac number, because 4250431485967 - 215 = 4250431453199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4250431485961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2125215742983 + 2125215742984.
It is an arithmetic number, because the mean of its divisors is an integer number (2125215742984).
It is a 2-persistent number, because it is pandigital, and so is 2⋅4250431485967 = 8500862971934, but 3⋅4250431485967 = 12751294457901 is not.
Almost surely, 24250431485967 is an apocalyptic number.
4250431485967 is a deficient number, since it is larger than the sum of its proper divisors (1).
4250431485967 is an equidigital number, since it uses as much as digits as its factorization.
4250431485967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29030400, while the sum is 58.
The spelling of 4250431485967 in words is "four trillion, two hundred fifty billion, four hundred thirty-one million, four hundred eighty-five thousand, nine hundred sixty-seven".
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