Base | Representation |
---|---|
bin | 10011010111111000101010… |
… | …11100100111110010001111 |
3 | 12120211201120102020012121111 |
4 | 21223330111130213302033 |
5 | 21040443140422333201 |
6 | 230335053024312451 |
7 | 11654621516555626 |
oct | 1153742534476217 |
9 | 176751512205544 |
10 | 42602140433551 |
11 | 126355147038a6 |
12 | 49406b6772727 |
13 | 1aa049806315a |
14 | a73d515c26bd |
15 | 4dd2a5919b51 |
hex | 26bf15727c8f |
42602140433551 has 2 divisors, whose sum is σ = 42602140433552. Its totient is φ = 42602140433550.
The previous prime is 42602140433513. The next prime is 42602140433591. The reversal of 42602140433551 is 15533404120624.
It is an a-pointer prime, because the next prime (42602140433591) can be obtained adding 42602140433551 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42602140433551 - 231 = 42599992949903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42602140433591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21301070216775 + 21301070216776.
It is an arithmetic number, because the mean of its divisors is an integer number (21301070216776).
Almost surely, 242602140433551 is an apocalyptic number.
42602140433551 is a deficient number, since it is larger than the sum of its proper divisors (1).
42602140433551 is an equidigital number, since it uses as much as digits as its factorization.
42602140433551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 42602140433551 in words is "forty-two trillion, six hundred two billion, one hundred forty million, four hundred thirty-three thousand, five hundred fifty-one".
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