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42850710211847 is a prime number
BaseRepresentation
bin10011011111000111101010…
…10111000100110100000111
312121201111011200010021101112
421233203311113010310013
521104031223303234342
6231045202225315235
712011601355042046
oct1157436527046407
9177644150107345
1042850710211847
111272097a88733a
124980908195b1b
131abaa5ca216c5
14a81db209655d
154e49a2dbe682
hex26f8f55c4d07

42850710211847 has 2 divisors, whose sum is σ = 42850710211848. Its totient is φ = 42850710211846.

The previous prime is 42850710211817. The next prime is 42850710211849. The reversal of 42850710211847 is 74811201705824.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42850710211847 - 28 = 42850710211591 is a prime.

Together with 42850710211849, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 42850710211795 and 42850710211804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42850710211849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21425355105923 + 21425355105924.

It is an arithmetic number, because the mean of its divisors is an integer number (21425355105924).

Almost surely, 242850710211847 is an apocalyptic number.

42850710211847 is a deficient number, since it is larger than the sum of its proper divisors (1).

42850710211847 is an equidigital number, since it uses as much as digits as its factorization.

42850710211847 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1003520, while the sum is 50.

The spelling of 42850710211847 in words is "forty-two trillion, eight hundred fifty billion, seven hundred ten million, two hundred eleven thousand, eight hundred forty-seven".