4300031131423 has 4 divisors (see below), whose sum is σ = 4304292808480. Its totient is φ = 4295769454368.

The previous prime is 4300031131387. The next prime is 4300031131469. The reversal of 4300031131423 is 3241311300034.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4300031131423 - 2²¹ = 4300029034271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4300031131493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2130837015 + ... + 2130839032.

It is an arithmetic number, because the mean of its divisors is an integer number (1076073202120).

Almost surely, 2^{4300031131423} is an apocalyptic number.

4300031131423 is a deficient number, since it is larger than the sum of its proper divisors (4261677057).

4300031131423 is a wasteful number, since it uses less digits than its factorization.

4300031131423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4261677056.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4300031131423 its reverse (3241311300034), we get a palindrome (7541342431457).

The spelling of 4300031131423 in words is "four trillion, three hundred billion, thirty-one million, one hundred thirty-one thousand, four hundred twenty-three".