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4300031131469 is a prime number
BaseRepresentation
bin111110100100101101110…
…100111111111101001101
3120020002010120012101000122
4332210231310333331031
51030422430432201334
613051223530234325
7622444531355663
oct76445564777515
916202116171018
104300031131469
1114086a6521457
1259545b8859a5
13252650207318
1410c1a0666c33
1576cc126832e
hex3e92dd3ff4d

4300031131469 has 2 divisors, whose sum is σ = 4300031131470. Its totient is φ = 4300031131468.

The previous prime is 4300031131387. The next prime is 4300031131471. The reversal of 4300031131469 is 9641311300034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2349972493444 + 1950058638025 = 1532962^2 + 1396445^2 .

It is a cyclic number.

It is not a de Polignac number, because 4300031131469 - 212 = 4300031127373 is a prime.

It is a super-2 number, since 2×43000311314692 (a number of 26 digits) contains 22 as substring.

Together with 4300031131471, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4300031131769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150015565734 + 2150015565735.

It is an arithmetic number, because the mean of its divisors is an integer number (2150015565735).

Almost surely, 24300031131469 is an apocalyptic number.

It is an amenable number.

4300031131469 is a deficient number, since it is larger than the sum of its proper divisors (1).

4300031131469 is an equidigital number, since it uses as much as digits as its factorization.

4300031131469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 4300031131469 in words is "four trillion, three hundred billion, thirty-one million, one hundred thirty-one thousand, four hundred sixty-nine".