Base | Representation |
---|---|
bin | 111110100100101101110… |
… | …100111111111101100101 |
3 | 120020002010120012101001112 |
4 | 332210231310333331211 |
5 | 1030422430432201433 |
6 | 13051223530234405 |
7 | 622444531356026 |
oct | 76445564777545 |
9 | 16202116171045 |
10 | 4300031131493 |
11 | 14086a6521479 |
12 | 59545b885a05 |
13 | 252650207336 |
14 | 10c1a0666c4d |
15 | 76cc1268348 |
hex | 3e92dd3ff65 |
4300031131493 has 2 divisors, whose sum is σ = 4300031131494. Its totient is φ = 4300031131492.
The previous prime is 4300031131481. The next prime is 4300031131549. The reversal of 4300031131493 is 3941311300034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3093651818884 + 1206379312609 = 1758878^2 + 1098353^2 .
It is a cyclic number.
It is not a de Polignac number, because 4300031131493 - 24 = 4300031131477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4300031131993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150015565746 + 2150015565747.
It is an arithmetic number, because the mean of its divisors is an integer number (2150015565747).
Almost surely, 24300031131493 is an apocalyptic number.
It is an amenable number.
4300031131493 is a deficient number, since it is larger than the sum of its proper divisors (1).
4300031131493 is an equidigital number, since it uses as much as digits as its factorization.
4300031131493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 32.
The spelling of 4300031131493 in words is "four trillion, three hundred billion, thirty-one million, one hundred thirty-one thousand, four hundred ninety-three".
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