Base | Representation |
---|---|
bin | 10011100011011110011000… |
… | …01011101000000111100111 |
3 | 12122020210101211222122222021 |
4 | 21301233030023220013213 |
5 | 21114004200324401411 |
6 | 231242030203444011 |
7 | 12025446406334434 |
oct | 1161571413500747 |
9 | 178223354878867 |
10 | 43000343200231 |
11 | 127793857a11aa |
12 | 49a5907b26607 |
13 | 1acbbb823c811 |
14 | a89328bccb8b |
15 | 4e880e654a71 |
hex | 271bcc2e81e7 |
43000343200231 has 2 divisors, whose sum is σ = 43000343200232. Its totient is φ = 43000343200230.
The previous prime is 43000343200187. The next prime is 43000343200247. The reversal of 43000343200231 is 13200234300034.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43000343200231 - 27 = 43000343200103 is a prime.
It is a super-2 number, since 2×430003432002312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43000343200196 and 43000343200205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43000343200261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21500171600115 + 21500171600116.
It is an arithmetic number, because the mean of its divisors is an integer number (21500171600116).
Almost surely, 243000343200231 is an apocalyptic number.
43000343200231 is a deficient number, since it is larger than the sum of its proper divisors (1).
43000343200231 is an equidigital number, since it uses as much as digits as its factorization.
43000343200231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 43000343200231 its reverse (13200234300034), we get a palindrome (56200577500265).
The spelling of 43000343200231 in words is "forty-three trillion, three hundred forty-three million, two hundred thousand, two hundred thirty-one".
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