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4300121132413 is a prime number
BaseRepresentation
bin111110100100110011001…
…100010100110101111101
3120020002100211112220002221
4332210303030110311331
51030423122002214123
613051240503245341
7622450003354261
oct76446314246575
916202324486087
104300121132413
1114087423034a7
12595485a49851
13252665a59812
1410c1ac5b40a1
1576cc90e525d
hex3e933314d7d

4300121132413 has 2 divisors, whose sum is σ = 4300121132414. Its totient is φ = 4300121132412.

The previous prime is 4300121132407. The next prime is 4300121132423. The reversal of 4300121132413 is 3142311210034.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2668132767364 + 1631988365049 = 1633442^2 + 1277493^2 .

It is a cyclic number.

It is not a de Polignac number, because 4300121132413 - 25 = 4300121132381 is a prime.

It is a super-2 number, since 2×43001211324132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4300121132423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150060566206 + 2150060566207.

It is an arithmetic number, because the mean of its divisors is an integer number (2150060566207).

Almost surely, 24300121132413 is an apocalyptic number.

It is an amenable number.

4300121132413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4300121132413 is an equidigital number, since it uses as much as digits as its factorization.

4300121132413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4300121132413 its reverse (3142311210034), we get a palindrome (7442432342447).

The spelling of 4300121132413 in words is "four trillion, three hundred billion, one hundred twenty-one million, one hundred thirty-two thousand, four hundred thirteen".