Base | Representation |
---|---|
bin | 1100100001001010010… |
… | …10000110001110101111 |
3 | 1112010012210220200121201 |
4 | 12100211022012032233 |
5 | 24021341223233201 |
6 | 525332223110331 |
7 | 43034530545313 |
oct | 6204512061657 |
9 | 1463183820551 |
10 | 430120133551 |
11 | 15645a669559 |
12 | 6b43a4423a7 |
13 | 31738876084 |
14 | 16b6455db43 |
15 | b2c5d52801 |
hex | 64252863af |
430120133551 has 2 divisors, whose sum is σ = 430120133552. Its totient is φ = 430120133550.
The previous prime is 430120133473. The next prime is 430120133563. The reversal of 430120133551 is 155331021034.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 430120133551 - 237 = 292681180079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (430120133851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215060066775 + 215060066776.
It is an arithmetic number, because the mean of its divisors is an integer number (215060066776).
Almost surely, 2430120133551 is an apocalyptic number.
430120133551 is a deficient number, since it is larger than the sum of its proper divisors (1).
430120133551 is an equidigital number, since it uses as much as digits as its factorization.
430120133551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 430120133551 its reverse (155331021034), we get a palindrome (585451154585).
The spelling of 430120133551 in words is "four hundred thirty billion, one hundred twenty million, one hundred thirty-three thousand, five hundred fifty-one".
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