Base | Representation |
---|---|
bin | 110000111001101000010101… |
… | …1111101100010110010111100 |
3 | 2002101222022202212002002000221 |
4 | 1201303100223331202302330 |
5 | 422334300113303012104 |
6 | 4122452232315231124 |
7 | 156413043515326456 |
oct | 14163205375426274 |
9 | 2071868685062027 |
10 | 430133122313404 |
11 | 115065483aa9084 |
12 | 402aa8204484a4 |
13 | 156014c169cc43 |
14 | 78307a8a252d6 |
15 | 34adb39e20c54 |
hex | 187342bf62cbc |
430133122313404 has 48 divisors (see below), whose sum is σ = 794963656053280. Its totient is φ = 203076417254400.
The previous prime is 430133122313393. The next prime is 430133122313407. The reversal of 430133122313404 is 404313221331034.
It is a super-2 number, since 2×4301331223134042 (a number of 30 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 430133122313404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (430133122313407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20318272 + ... + 35680504.
Almost surely, 2430133122313404 is an apocalyptic number.
It is an amenable number.
430133122313404 is a deficient number, since it is larger than the sum of its proper divisors (364830533739876).
430133122313404 is a wasteful number, since it uses less digits than its factorization.
430133122313404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15363470 (or 15363468 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 430133122313404 its reverse (404313221331034), we get a palindrome (834446343644438).
The spelling of 430133122313404 in words is "four hundred thirty trillion, one hundred thirty-three billion, one hundred twenty-two million, three hundred thirteen thousand, four hundred four".
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