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4301332331081 is a prime number
BaseRepresentation
bin111110100101111011011…
…000101011101001001001
3120020012111020122011022212
4332211323120223221021
51030433112034043311
613052001011354505
7622522011363602
oct76457330535111
916205436564285
104301332331081
111409203a68a35
125957635b2a35
132527c9972316
1410c2853bada9
1576d4a5e3c8b
hex3e97b62ba49

4301332331081 has 2 divisors, whose sum is σ = 4301332331082. Its totient is φ = 4301332331080.

The previous prime is 4301332331033. The next prime is 4301332331083. The reversal of 4301332331081 is 1801332331034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4219158375481 + 82173955600 = 2054059^2 + 286660^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4301332331081 is a prime.

It is a super-2 number, since 2×43013323310812 (a number of 26 digits) contains 22 as substring.

Together with 4301332331083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4301332331083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150666165540 + 2150666165541.

It is an arithmetic number, because the mean of its divisors is an integer number (2150666165541).

Almost surely, 24301332331081 is an apocalyptic number.

It is an amenable number.

4301332331081 is a deficient number, since it is larger than the sum of its proper divisors (1).

4301332331081 is an equidigital number, since it uses as much as digits as its factorization.

4301332331081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 4301332331081 in words is "four trillion, three hundred one billion, three hundred thirty-two million, three hundred thirty-one thousand, eighty-one".