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4306126980119 is a prime number
BaseRepresentation
bin111110101010011001001…
…010110100010000010111
3120020122212101121120022212
4332222121022310100113
51031022422001330434
613054112445344035
7623051561256326
oct76523112642027
916218771546285
104306126980119
1114102444687a8
1259668126801b
132530b20c2163
1410c5bc0a60bd
157702b4d58ce
hex3ea992b4417

4306126980119 has 2 divisors, whose sum is σ = 4306126980120. Its totient is φ = 4306126980118.

The previous prime is 4306126980019. The next prime is 4306126980121. The reversal of 4306126980119 is 9110896216034.

4306126980119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4306126980119 is a prime.

It is a super-2 number, since 2×43061269801192 (a number of 26 digits) contains 22 as substring.

Together with 4306126980121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4306126980019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2153063490059 + 2153063490060.

It is an arithmetic number, because the mean of its divisors is an integer number (2153063490060).

Almost surely, 24306126980119 is an apocalyptic number.

4306126980119 is a deficient number, since it is larger than the sum of its proper divisors (1).

4306126980119 is an equidigital number, since it uses as much as digits as its factorization.

4306126980119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 50.

The spelling of 4306126980119 in words is "four trillion, three hundred six billion, one hundred twenty-six million, nine hundred eighty thousand, one hundred nineteen".