Search a number
-
+
4310024030021 is a prime number
BaseRepresentation
bin111110101110000001011…
…100111000011101000101
3120021000220222121012210102
4332232001130320131011
51031103412122430041
613055555300533445
7623250261533003
oct76560134703505
916230828535712
104310024030021
111411964225aa6
1259738a3b1285
132535835a9348
1410c86b89ba73
15771a86c209b
hex3eb81738745

4310024030021 has 2 divisors, whose sum is σ = 4310024030022. Its totient is φ = 4310024030020.

The previous prime is 4310024029999. The next prime is 4310024030023. The reversal of 4310024030021 is 1200304200134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4308239896900 + 1784133121 = 2075630^2 + 42239^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4310024030021 is a prime.

Together with 4310024030023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4310024029975 and 4310024030002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4310024030023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155012015010 + 2155012015011.

It is an arithmetic number, because the mean of its divisors is an integer number (2155012015011).

Almost surely, 24310024030021 is an apocalyptic number.

It is an amenable number.

4310024030021 is a deficient number, since it is larger than the sum of its proper divisors (1).

4310024030021 is an equidigital number, since it uses as much as digits as its factorization.

4310024030021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 4310024030021 its reverse (1200304200134), we get a palindrome (5510328230155).

The spelling of 4310024030021 in words is "four trillion, three hundred ten billion, twenty-four million, thirty thousand, twenty-one".