Base | Representation |
---|---|
bin | 1100100010110101111… |
… | …10110001011001011101 |
3 | 1112012112202001212202221 |
4 | 12101122332301121131 |
5 | 24030213410244201 |
6 | 530002001345341 |
7 | 43066104122464 |
oct | 6213276613135 |
9 | 1465482055687 |
10 | 431023134301 |
11 | 156883360371 |
12 | 6b650938251 |
13 | 31850980546 |
14 | 16c0c45b9db |
15 | b32a2734a1 |
hex | 645afb165d |
431023134301 has 2 divisors, whose sum is σ = 431023134302. Its totient is φ = 431023134300.
The previous prime is 431023134181. The next prime is 431023134331. The reversal of 431023134301 is 103431320134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 428567931801 + 2455202500 = 654651^2 + 49550^2 .
It is a cyclic number.
It is not a de Polignac number, because 431023134301 - 213 = 431023126109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (431023134331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215511567150 + 215511567151.
It is an arithmetic number, because the mean of its divisors is an integer number (215511567151).
Almost surely, 2431023134301 is an apocalyptic number.
It is an amenable number.
431023134301 is a deficient number, since it is larger than the sum of its proper divisors (1).
431023134301 is an equidigital number, since it uses as much as digits as its factorization.
431023134301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 431023134301 its reverse (103431320134), we get a palindrome (534454454435).
The spelling of 431023134301 in words is "four hundred thirty-one billion, twenty-three million, one hundred thirty-four thousand, three hundred one".
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