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43105509719 is a prime number
BaseRepresentation
bin101000001001010010…
…011110000101010111
311010021002121202221222
4220021102132011113
51201240002302334
631445152400555
73054123533666
oct501122360527
9133232552858
1043105509719
111730aa334a8
12842bb4615b
1340ac58938c
14212cbdaddd
1511c446cd2e
hexa0949e157

43105509719 has 2 divisors, whose sum is σ = 43105509720. Its totient is φ = 43105509718.

The previous prime is 43105509701. The next prime is 43105509721. The reversal of 43105509719 is 91790550134.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43105509719 is a prime.

It is a super-2 number, since 2×431055097192 (a number of 22 digits) contains 22 as substring.

Together with 43105509721, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43105509719.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43105509319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21552754859 + 21552754860.

It is an arithmetic number, because the mean of its divisors is an integer number (21552754860).

Almost surely, 243105509719 is an apocalyptic number.

43105509719 is a deficient number, since it is larger than the sum of its proper divisors (1).

43105509719 is an equidigital number, since it uses as much as digits as its factorization.

43105509719 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 170100, while the sum is 44.

The spelling of 43105509719 in words is "forty-three billion, one hundred five million, five hundred nine thousand, seven hundred nineteen".