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431124131312543 is a prime number
BaseRepresentation
bin110001000000110101110100…
…0101100110111001110011111
32002112111001201222100100000002
41202001223220230313032133
5423002014210104000133
64124531405225324515
7156544455606665144
oct14201535054671637
92075431658310002
10431124131312543
11115407798819a49
124042a8b333673b
1315673aa6019616
14786673ad1a3cb
1534c97dc186ce8
hex1881ae8b3739f

431124131312543 has 2 divisors, whose sum is σ = 431124131312544. Its totient is φ = 431124131312542.

The previous prime is 431124131312527. The next prime is 431124131312549. The reversal of 431124131312543 is 345213131421134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431124131312543 - 24 = 431124131312527 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 431124131312497 and 431124131312506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431124131312549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215562065656271 + 215562065656272.

It is an arithmetic number, because the mean of its divisors is an integer number (215562065656272).

Almost surely, 2431124131312543 is an apocalyptic number.

431124131312543 is a deficient number, since it is larger than the sum of its proper divisors (1).

431124131312543 is an equidigital number, since it uses as much as digits as its factorization.

431124131312543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 103680, while the sum is 38.

Adding to 431124131312543 its reverse (345213131421134), we get a palindrome (776337262733677).

The spelling of 431124131312543 in words is "four hundred thirty-one trillion, one hundred twenty-four billion, one hundred thirty-one million, three hundred twelve thousand, five hundred forty-three".