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4311317053 is a prime number
BaseRepresentation
bin1000000001111100…
…10111101000111101
3102010110111121011101
410000332113220331
532312144121203
61551450253101
7211560406321
oct40076275075
912113447141
104311317053
11191269834a
12a03a27191
135392826a4
142cc831981
151a376c41d
hex100f97a3d

4311317053 has 2 divisors, whose sum is σ = 4311317054. Its totient is φ = 4311317052.

The previous prime is 4311317029. The next prime is 4311317077. The reversal of 4311317053 is 3507131134.

It is a balanced prime because it is at equal distance from previous prime (4311317029) and next prime (4311317077).

It can be written as a sum of positive squares in only one way, i.e., 2809212004 + 1502105049 = 53002^2 + 38757^2 .

It is a cyclic number.

It is not a de Polignac number, because 4311317053 - 213 = 4311308861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311317753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155658526 + 2155658527.

It is an arithmetic number, because the mean of its divisors is an integer number (2155658527).

Almost surely, 24311317053 is an apocalyptic number.

It is an amenable number.

4311317053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311317053 is an equidigital number, since it uses as much as digits as its factorization.

4311317053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 28.

The square root of 4311317053 is about 65660.6202605489. The cubic root of 4311317053 is about 1627.5586739929.

Adding to 4311317053 its reverse (3507131134), we get a palindrome (7818448187).

The spelling of 4311317053 in words is "four billion, three hundred eleven million, three hundred seventeen thousand, fifty-three".