Base | Representation |
---|---|
bin | 1100100011000010111… |
… | …10100001100101001011 |
3 | 1112012211100010222222212 |
4 | 12101201132201211023 |
5 | 24030424310341134 |
6 | 530020453335335 |
7 | 43101566365256 |
oct | 6214136414513 |
9 | 1465740128885 |
10 | 431132121419 |
11 | 15692992aa6a |
12 | 6b68133754b |
13 | 3186a41c86c |
14 | 16c1cb0c09d |
15 | b334b00bce |
hex | 64617a194b |
431132121419 has 2 divisors, whose sum is σ = 431132121420. Its totient is φ = 431132121418.
The previous prime is 431132121401. The next prime is 431132121421. The reversal of 431132121419 is 914121231134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 431132121419 - 228 = 430863685963 is a prime.
It is a super-2 number, since 2×4311321214192 (a number of 24 digits) contains 22 as substring.
Together with 431132121421, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (431132121919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215566060709 + 215566060710.
It is an arithmetic number, because the mean of its divisors is an integer number (215566060710).
Almost surely, 2431132121419 is an apocalyptic number.
431132121419 is a deficient number, since it is larger than the sum of its proper divisors (1).
431132121419 is an equidigital number, since it uses as much as digits as its factorization.
431132121419 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 32.
The spelling of 431132121419 in words is "four hundred thirty-one billion, one hundred thirty-two million, one hundred twenty-one thousand, four hundred nineteen".
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