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43114150151 is a prime number
BaseRepresentation
bin101000001001110011…
…011011100100000111
311010021200212202101222
4220021303123210013
51201244210301101
631450101510555
73054260141522
oct501163334407
9133250782358
1043114150151
11173148a5156
128432a1245b
1340b12c3167
142130009bb9
1511c50c801b
hexa09cdb907

43114150151 has 2 divisors, whose sum is σ = 43114150152. Its totient is φ = 43114150150.

The previous prime is 43114150139. The next prime is 43114150153. The reversal of 43114150151 is 15105141134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43114150151 - 214 = 43114133767 is a prime.

Together with 43114150153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43114150151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43114150153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21557075075 + 21557075076.

It is an arithmetic number, because the mean of its divisors is an integer number (21557075076).

Almost surely, 243114150151 is an apocalyptic number.

43114150151 is a deficient number, since it is larger than the sum of its proper divisors (1).

43114150151 is an equidigital number, since it uses as much as digits as its factorization.

43114150151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 43114150151 its reverse (15105141134), we get a palindrome (58219291285).

The spelling of 43114150151 in words is "forty-three billion, one hundred fourteen million, one hundred fifty thousand, one hundred fifty-one".