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4311434442253 is a prime number
BaseRepresentation
bin111110101111010101100…
…001001011011000001101
3120021011120021112120122111
4332233111201023120031
51031114304204123003
613100351242544021
7623330236043011
oct76572541133015
916234507476574
104311434442253
111412518386644
12597702808011
132537498621b3
1410c962d20541
157723c421e6d
hex3ebd584b60d

4311434442253 has 2 divisors, whose sum is σ = 4311434442254. Its totient is φ = 4311434442252.

The previous prime is 4311434442251. The next prime is 4311434442353. The reversal of 4311434442253 is 3522444341134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2656437100164 + 1654997342089 = 1629858^2 + 1286467^2 .

It is a cyclic number.

It is not a de Polignac number, because 4311434442253 - 21 = 4311434442251 is a prime.

Together with 4311434442251, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311434442251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155717221126 + 2155717221127.

It is an arithmetic number, because the mean of its divisors is an integer number (2155717221127).

Almost surely, 24311434442253 is an apocalyptic number.

It is an amenable number.

4311434442253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311434442253 is an equidigital number, since it uses as much as digits as its factorization.

4311434442253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 552960, while the sum is 40.

Adding to 4311434442253 its reverse (3522444341134), we get a palindrome (7833878783387).

The spelling of 4311434442253 in words is "four trillion, three hundred eleven billion, four hundred thirty-four million, four hundred forty-two thousand, two hundred fifty-three".