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4312040121421 is a prime number
BaseRepresentation
bin111110101111111001100…
…111101010010001001101
3120021020010111020021021021
4332233321213222101031
51031122024232341141
613100531320434141
7623351242164334
oct76577147522115
916236114207237
104312040121421
1114127a926333a
12597851618951
13253815198a36
1410c9bd544d1b
15772756b26d1
hex3ebf99ea44d

4312040121421 has 2 divisors, whose sum is σ = 4312040121422. Its totient is φ = 4312040121420.

The previous prime is 4312040121331. The next prime is 4312040121457. The reversal of 4312040121421 is 1241210402134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2878488885321 + 1433551236100 = 1696611^2 + 1197310^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312040121421 - 221 = 4312038024269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4312040121721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156020060710 + 2156020060711.

It is an arithmetic number, because the mean of its divisors is an integer number (2156020060711).

Almost surely, 24312040121421 is an apocalyptic number.

It is an amenable number.

4312040121421 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312040121421 is an equidigital number, since it uses as much as digits as its factorization.

4312040121421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4312040121421 its reverse (1241210402134), we get a palindrome (5553250523555).

The spelling of 4312040121421 in words is "four trillion, three hundred twelve billion, forty million, one hundred twenty-one thousand, four hundred twenty-one".