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4312100381 is a prime number
BaseRepresentation
bin1000000010000010…
…10110111000011101
3102010111222101200112
410001001112320131
532312344203011
61551515135405
7211600151141
oct40101267035
912114871615
104312100381
111913082926
12a04144565
135394980b4
142cc997221
151a387458b
hex101056e1d

4312100381 has 2 divisors, whose sum is σ = 4312100382. Its totient is φ = 4312100380.

The previous prime is 4312100357. The next prime is 4312100383. The reversal of 4312100381 is 1830012134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4255474756 + 56625625 = 65234^2 + 7525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4312100381 is a prime.

It is a super-2 number, since 2×43121003812 = 37188419391640690322, which contains 22 as substring.

Together with 4312100383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4312100383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156050190 + 2156050191.

It is an arithmetic number, because the mean of its divisors is an integer number (2156050191).

Almost surely, 24312100381 is an apocalyptic number.

It is an amenable number.

4312100381 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312100381 is an equidigital number, since it uses as much as digits as its factorization.

4312100381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

The square root of 4312100381 is about 65666.5849652622. The cubic root of 4312100381 is about 1627.6572390068.

The spelling of 4312100381 in words is "four billion, three hundred twelve million, one hundred thousand, three hundred eighty-one".