Base | Representation |
---|---|
bin | 111110110000000101100… |
… | …111101010000001100011 |
3 | 120021020122112001200001121 |
4 | 332300011213222001203 |
5 | 1031122432302301021 |
6 | 13101003311513111 |
7 | 623356235342401 |
oct | 76600547520143 |
9 | 16236575050047 |
10 | 4312241447011 |
11 | 14128a1971223 |
12 | 5978a8b28797 |
13 | 253847ac84c4 |
14 | 10c9dc190471 |
15 | 772881ce741 |
hex | 3ec059ea063 |
4312241447011 has 2 divisors, whose sum is σ = 4312241447012. Its totient is φ = 4312241447010.
The previous prime is 4312241447009. The next prime is 4312241447029. The reversal of 4312241447011 is 1107441422134.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4312241447011 - 21 = 4312241447009 is a prime.
Together with 4312241447009, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4312241457011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156120723505 + 2156120723506.
It is an arithmetic number, because the mean of its divisors is an integer number (2156120723506).
Almost surely, 24312241447011 is an apocalyptic number.
4312241447011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312241447011 is an equidigital number, since it uses as much as digits as its factorization.
4312241447011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 4312241447011 its reverse (1107441422134), we get a palindrome (5419682869145).
The spelling of 4312241447011 in words is "four trillion, three hundred twelve billion, two hundred forty-one million, four hundred forty-seven thousand, eleven".
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