Base | Representation |
---|---|
bin | 1100100011011000001… |
… | …01100011000011101001 |
3 | 1112020021202002102120221 |
4 | 12101230011203003221 |
5 | 24031310342420431 |
6 | 530050252450041 |
7 | 43106160362104 |
oct | 6215405430351 |
9 | 1466252072527 |
10 | 431310123241 |
11 | 156a10358408 |
12 | 6b710a79921 |
13 | 3189827409a |
14 | 16c3860573b |
15 | b345562111 |
hex | 646c1630e9 |
431310123241 has 2 divisors, whose sum is σ = 431310123242. Its totient is φ = 431310123240.
The previous prime is 431310123239. The next prime is 431310123331. The reversal of 431310123241 is 142321013134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 430992250000 + 317873241 = 656500^2 + 17829^2 .
It is a cyclic number.
It is not a de Polignac number, because 431310123241 - 21 = 431310123239 is a prime.
Together with 431310123239, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (431310123341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215655061620 + 215655061621.
It is an arithmetic number, because the mean of its divisors is an integer number (215655061621).
Almost surely, 2431310123241 is an apocalyptic number.
It is an amenable number.
431310123241 is a deficient number, since it is larger than the sum of its proper divisors (1).
431310123241 is an equidigital number, since it uses as much as digits as its factorization.
431310123241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 431310123241 its reverse (142321013134), we get a palindrome (573631136375).
The spelling of 431310123241 in words is "four hundred thirty-one billion, three hundred ten million, one hundred twenty-three thousand, two hundred forty-one".
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