Base | Representation |
---|---|
bin | 1100100011100010110… |
… | …00101001001011101011 |
3 | 1112020111221100121100202 |
4 | 12101301120221023223 |
5 | 24032001121441042 |
6 | 530103150022415 |
7 | 43111320061142 |
oct | 6216130511353 |
9 | 1466457317322 |
10 | 431399015147 |
11 | 156a565521a1 |
12 | 6b7367a7a0b |
13 | 318b07c8849 |
14 | 16c46344759 |
15 | b34d270632 |
hex | 64716292eb |
431399015147 has 2 divisors, whose sum is σ = 431399015148. Its totient is φ = 431399015146.
The previous prime is 431399015141. The next prime is 431399015149. The reversal of 431399015147 is 741510993134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 431399015147 - 218 = 431398753003 is a prime.
It is a super-2 number, since 2×4313990151472 (a number of 24 digits) contains 22 as substring.
Together with 431399015149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (431399015141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215699507573 + 215699507574.
It is an arithmetic number, because the mean of its divisors is an integer number (215699507574).
Almost surely, 2431399015147 is an apocalyptic number.
431399015147 is a deficient number, since it is larger than the sum of its proper divisors (1).
431399015147 is an equidigital number, since it uses as much as digits as its factorization.
431399015147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 408240, while the sum is 47.
The spelling of 431399015147 in words is "four hundred thirty-one billion, three hundred ninety-nine million, fifteen thousand, one hundred forty-seven".
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