Base | Representation |
---|---|
bin | 111110110001110110011… |
… | …111000101011010011011 |
3 | 120021102112111011102011002 |
4 | 332301312133011122123 |
5 | 1031140322031302212 |
6 | 13101515233455215 |
7 | 623454200445002 |
oct | 76616637053233 |
9 | 16242474142132 |
10 | 4314135025307 |
11 | 1413683830668 |
12 | 59813711150b |
13 | 253a8a1c1133 |
14 | 10cb3b865c39 |
15 | 7734956eac2 |
hex | 3ec767c569b |
4314135025307 has 2 divisors, whose sum is σ = 4314135025308. Its totient is φ = 4314135025306.
The previous prime is 4314135025301. The next prime is 4314135025309. The reversal of 4314135025307 is 7035205314134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4314135025307 - 212 = 4314135021211 is a prime.
It is a super-2 number, since 2×43141350253072 (a number of 26 digits) contains 22 as substring.
Together with 4314135025309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4314135025301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157067512653 + 2157067512654.
It is an arithmetic number, because the mean of its divisors is an integer number (2157067512654).
Almost surely, 24314135025307 is an apocalyptic number.
4314135025307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4314135025307 is an equidigital number, since it uses as much as digits as its factorization.
4314135025307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 38.
The spelling of 4314135025307 in words is "four trillion, three hundred fourteen billion, one hundred thirty-five million, twenty-five thousand, three hundred seven".
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