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4314135025307 is a prime number
BaseRepresentation
bin111110110001110110011…
…111000101011010011011
3120021102112111011102011002
4332301312133011122123
51031140322031302212
613101515233455215
7623454200445002
oct76616637053233
916242474142132
104314135025307
111413683830668
1259813711150b
13253a8a1c1133
1410cb3b865c39
157734956eac2
hex3ec767c569b

4314135025307 has 2 divisors, whose sum is σ = 4314135025308. Its totient is φ = 4314135025306.

The previous prime is 4314135025301. The next prime is 4314135025309. The reversal of 4314135025307 is 7035205314134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4314135025307 - 212 = 4314135021211 is a prime.

It is a super-2 number, since 2×43141350253072 (a number of 26 digits) contains 22 as substring.

Together with 4314135025309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4314135025301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157067512653 + 2157067512654.

It is an arithmetic number, because the mean of its divisors is an integer number (2157067512654).

Almost surely, 24314135025307 is an apocalyptic number.

4314135025307 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314135025307 is an equidigital number, since it uses as much as digits as its factorization.

4314135025307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 4314135025307 in words is "four trillion, three hundred fourteen billion, one hundred thirty-five million, twenty-five thousand, three hundred seven".